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5x^2-16x-884=0
a = 5; b = -16; c = -884;
Δ = b2-4ac
Δ = -162-4·5·(-884)
Δ = 17936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17936}=\sqrt{16*1121}=\sqrt{16}*\sqrt{1121}=4\sqrt{1121}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{1121}}{2*5}=\frac{16-4\sqrt{1121}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{1121}}{2*5}=\frac{16+4\sqrt{1121}}{10} $
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